Ta có: \(\dfrac{6}{7}=\dfrac{6\times15}{7\times15}=\dfrac{90}{105}và\dfrac{17}{15}=\dfrac{17\times7}{15\times7}=\dfrac{119}{105}\)
\(\Rightarrow x=\left\{\dfrac{91}{105};\dfrac{92}{105};\dfrac{93}{105};...;\dfrac{118}{105}\right\}\)
Vậy \(x=\dfrac{91}{105};\dfrac{92}{105};\dfrac{93}{105};...;\dfrac{118}{105}.\)