(1/1.2.3+1/2.3.4+...+1/8.9.10).x=22/45
<=>(2/1.2.3+2/2.3.4+...+2/8.9.10).x=44/45
<=>(1/1.2-1/2.3+1/2.3-1/3.4+...+1/8.9-1/9.10).x=44/45
<=>(1/1.2-1/9.10).x=44/45
<=>22/45.x=44/45<=>x=2
vậy x=2
Tim so tu nhien x biet (1/1.2.3+1/2.3.4+...1/8.9.10)x=22/45
tim so tu nhien x biet (1/1.2.3+1/2.3.4+...+1/8.9.10)x=22/45
tim so tu nhien x biet (1/1.2.3 + 1/2.3.4 +...+ 1/8.9.10).x =23/45
tìm so tu nhien x biet (1/1.2.3 + 1/2.3.4+...+ 1/8.9.10).x=23/45
Tim x biet: \(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...\frac{1}{8.9.10}\right)x=\frac{22}{45}\)
Tim x biet
\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}\right).x=\frac{23}{45}\)
(1/1.2.3+1/2.3.4+...+1/8.9.10).x=22/45
tìm x biết:(1/1.2.3+2/2.3.4+...+1/8.9.10).x=22/45
Tìm x:
(1/1.2.3+1/2.3.4+...+1/8.9.10).x=22/45
