\(\left(2x+1\right)\left(x+\frac{1}{2}\right)< 0\)
\(\Rightarrow\orbr{\begin{cases}2x+1< 0\\x+\frac{1}{2}< 0\end{cases}}\) \(\Rightarrow\hept{\begin{cases}2x< -1\\x< 0-\frac{1}{2}\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x< -\frac{1}{2}\\x< \frac{1}{2}\end{cases}}\)
\(\Rightarrow-\frac{1}{2}< x< \frac{1}{2};x\in Z\Rightarrow x=-1\)
Vậy: \(x=-1\)