Question

Tìm số nguyên x biết:

a, -45 : (3x - 17) = 3^2

b, (2x - 8).(-2x) = 0

c, 72 : |4x - 3| = 2^3

d, 2^(x+1) = 32

Answer 1

a) -45 : ( 3x - 17 ) = 3²

3x - 17 = -45 : 9

3x - 17 = -5

3x = 12

x = 4

Answer 2

b) \(\left(2x-8\right)\left(-2x\right)=0\)

\(\Rightarrow\orbr{\begin{cases}2x-8=0\\-2x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=4\\x=0\end{cases}}\)

Vậy.....

Answer 3

c) \(72:\left|4x-3\right|=2^3\)

\(\left|4x-3\right|=9\)

\(\Rightarrow\orbr{\begin{cases}4x-3=9\\4x-3=-9\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=3\\x=\frac{-3}{2}\end{cases}}\)

Vậy.....

Answer 4

d) \(2^{x+1}=32\)

\(2^{x+1}=2^5\)

\(\Rightarrow x+1=5\)

\(\Rightarrow x=4\)

Vậy.....