\(5.\left(x-7\right)-4.\left(x+3\right)=-31\)
\(5x-35-\left(4x+12\right)=-31\)
\(5x-35-4x-12=-31\)
\(5x-4x=-31+35+12\)
\(x=16\in Z\)
VẬY \(x=16\)
5.(x-7)-4.(x+3)=-31
=> 5x-35-4x-12= -31
=> 5x-4x = -31 + 35 + 12
=> x = 16
Vậy x=16
a) 5(x-7)- 4(x+3) = -31
<=> 5x - 35 - ( 4x + 12 ) = -31
<=> 5x - 35 - 4x - 12 = -31
<=> 5x - 4x = -31 + 35 + 12
<=> x = 16
Vậy x = 16