33n+1 = 9n+2
33n+1 = 32(n+2)
33n+1 = 32n+4
3n + 1 = 2n + 4
2n - 3n = 1 - 4
-n = -3
n = 3
\(3^{3n+1}=9^{n+2}=\left(3^2\right)^{2n+2}=2^{4n+4}=>3n+1=4n+4=>n=-3\)
ta có : 9n+2=(32)n+2=32(n+2)=32n+4
33n+1=9n+2
=>33n+1=32n+4
=>3n+1=2n+4
=>3n-2n=4-1
=>n=3
vậy n=3