Question

tìm số hữu tỉ x sao cho

x+1/2023 + x+2/2022=x+3/2021 + x+4/2020

Answer 1

`{x+1}/2023 +{x+2}/2022={x+3}/2021+{x+4}/2020`

`{x+1}/2023+{x+2}/2022-{x+3}/2021-{x+4}/2020=0`

`({x+1}/2023+1)+({x+2}/2022+1)-({x+3}/2021+1)-({x+4}/2020+1)=0`

`{x+2024}/2023+{x+2024}/2022-{x+2024}/2021-{x+2024}/2020=0`

`x+2024(1/2023+1/2022-1/2021-1/2020)=0`

`x+2024=0` (vì `1/2023+1/2022-1/2021-1/2020 ne 0`)

`x=-2024`

Vậy `x=-2024`