Question

Tìm n:

a. 4¹⁵. 9¹⁵ < 2ⁿ . 3ⁿ < 18⁶ . 2¹⁶

^b. 4¹¹. 25¹¹ < 2ⁿ . 5ⁿ < 20¹² . 5¹²

^{c. \(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^6}{2^5+2^5}=2^n\)}

Answer 1

C.\(\frac{4^5.\left(1+1+1+1\right)}{3^5.\left(1+1+1\right)}.\frac{6^6}{2^{5+}2^5}=\frac{4^6}{3^6}.\frac{6^6}{2^5+2^5}=\frac{24^6}{3^6.\left(2^5+2^5\right)}=\frac{8^6}{2^5.\left(1+1\right)}\)=\(\frac{8^6}{2^6}\)=4^6=4096

Answer 2

\(^{4^6=2^{12}}\)

           \(\Rightarrow\)n=12