Ta có:\(\left|x+5\right|+\left|x-4\right|=\left|x+5\right|+\left|4-x\right|>\left|x+5+4-x\right|\)-x| =9
Dấu ''='' xảy ra <=>(x+5)(4-x)>0
<=>-5<=x<=4
Vậy min(A)=9<=>-5<=x<=4
tìm MIN A
A= I x- 5I + I x+ 4I
Tìm x,y biết
a) 2 I 2x-3 I = \(\frac{1}{2}\)
b) 7,5-3 I5-2xI= -4,5
c) I3x-4I+I3y+5I=0
d) 3,7+I4,3-xI=0
e) 4-I5x-2I=1
tìm x :
a) I x+1/101I+ I x+2/101 I +.........+ I x+100/101I = 101x
b) I x+5I- I1-2xI =x
tìm x :
a) I x+1/101I+ I x+2/101 I +.........+ I x+100/101I = 101x
b) I x+5I- I1-2xI =x
tìm x :
a) I x+1/101I+ I x+2/101 I +.........+ I x+100/101I = 101x
b) I x+5I- I1-2xI =x
tìm x :
a) I x+1/101I+ I x+2/101 I +.........+ I x+100/101I = 101x
b) I x+5I- I1-2xI =x
tìm x :
a) I x+1/101I+ I x+2/101 I +.........+ I x+100/101I = 101x
b) I x+5I- I1-2xI =x
Giải pt gia tri tuyet doi
Ix-3I -x =7
Ix^2+Ix-1II=x^2 +2
Ix-1/3I+4/5=I-3,2+2/5I
IIx-2I-4I=10
Ix+11/7I+Ix+2/7I+Ix+4/7I=4x
Tìm x
a) I 5-Ix-4I+2x I=10
b) I x+6I +I4x-1I+2x =3
