Question

tìm mẫu thức chung và quy đồng từng phân thức sau

Answer 1

i: MTC=(x-1)(x^2+1)

\(\dfrac{1}{x-1}=\dfrac{x^2+1}{\left(x-1\right)\left(x^2+1\right)}\)

\(\dfrac{2x}{x^3-x^2+x-1}=\dfrac{2x}{\left(x-1\right)\left(x^2+1\right)}\)

k: MTC=2(3x+1)(3x-1)

\(\dfrac{3x-1}{6x+2}=\dfrac{3x-1}{2\left(3x+1\right)}=\dfrac{\left(3x-1\right)^2}{2\left(3x+1\right)\left(3x-1\right)}\)

\(\dfrac{3x+1}{2-6x}=\dfrac{-\left(3x+1\right)}{2\left(3x-1\right)}=\dfrac{-\left(3x+1\right)^2}{2\left(3x-1\right)\left(3x+1\right)}\)

\(\dfrac{6x}{9x^2-1}=\dfrac{12x}{2\left(3x-1\right)\left(3x+1\right)}\)