b: Ox: y=0
=>0x+y+0=0
M thuộc Δ nên M(-2y+2;y)
\(d\left(M;\text{Δ}\right)=\dfrac{\left|\left(-2y+2\right)\cdot0+y\cdot1+0\right|}{\sqrt{0^2+1^2}}=\sqrt{2}\)
=>|y|=căn 2
=>y=căn 2 hoặc y=-căn 2
=>\(M\left(2-2\sqrt{2};\sqrt{2}\right)\) hoặc \(M\left(2+2\sqrt{2};-\sqrt{2}\right)\)
c: Oy: x=0
=>x+0y+0=0
x+2y-2=0
=>2y=-x+2
=>y=-0,5x+1
=>M(x;-0,5x+1)
d(M;Oy)=căn 3; M(x;-0,5x+1); x+0y+0=0(Oy)
=>\(\dfrac{\left|x\cdot1+\left(-0.5x+1\right)\cdot0+0\right|}{\sqrt{1^2+0^2}}=\sqrt{3}\)
=>\(\left|x\right|=\sqrt{3}\)
=>\(\left[{}\begin{matrix}x=\sqrt{3}\\x=-\sqrt{3}\end{matrix}\right.\)
=>\(M\left(\sqrt{3};\dfrac{2-\sqrt{3}}{2}\right)\) hoặc \(M\left(-\sqrt{3};\dfrac{2+\sqrt{3}}{2}\right)\)
