dat x-2=y=> x=y+2
{nhan phan phoi ra de hon la ghep}
\(\frac{6\left(y+2\right)^2+5m\left(y+2\right)-4}{y}=\frac{6^{ }\left(y^2+4y+4\right)+5my+10m-4}{y}\)
\(\frac{6y^2+24y+24+5my+10m-4}{y}=\left(6y+24+5m\right)+\frac{10m+20}{y}\)
so du: =10m+20
dau bai so du la 10=> 10m+20=10=> m=-1