Đặt \(f\left(x\right)=35x^3+41x^2+13x-2m\)
Để \(f\left(x\right)⋮\left(5x-2\right)\Rightarrow f\left(\dfrac{2}{5}\right)=0\)
\(\Rightarrow35.\left(\dfrac{2}{5}\right)^3+41.\left(\dfrac{2}{5}\right)^2+13.\left(\dfrac{2}{5}\right)-2m=0\)
\(\Leftrightarrow14-2m=0\)
\(\Leftrightarrow m=7\)