Vì \(a>0\)nên :
Khi \(a=1\)
\(\Rightarrow b-2=3\)
\(\Rightarrow b=5\)
Khi \(a=3\)
\(\Rightarrow b-2=1\)
\(\Rightarrow b=3\)
Vậy \(\left(a;b\right)\in\left\{\left(1;5\right);\left(3;3\right)\right\}\)
tim hai so nguyen a,b biet :b biet :a>0 va a .(b-2)=3
tim hai so nguyen a,b biet a>0 va (a+5)*(b-2)=(-3)
Tim hai so nguyen a , b biet : a > 0 va a . (b - 2) = 3
tim so nguyen a, b biet a lon hon 0 va a.(b-2)=3
tim x,y biet (x-2).(y+1)=23
tim 2 so nguyen to a va b biet a^2-b^2-1=0
Bai 1: a)Tim so tu nhien a biet 1960va2002 chia cho a cung co so du la 28
b)Tim 2 sop tu nhien a va b , biet :BCNN(a,b)=300;UCLN(a,b)=15 va a+15=b
Bai 2:a)Tong sau la binh phuong so nao ?
S=1+3+5+7+...+199
b) Cho so ab va so ababab
1)chung to ababab la boi cua ab
2)So 3 va 10101 co phai la uoc cua ababab khong , vi sao?
Bai 3
a)Hay viet them dang sau so 664 ba chu so de nhan duoc sdo co 6 chu so chia het cho 5,9,11
b)Tim so nguyen x thuoc Z biet rang :
(x^2-1)(x^2-4)<0
Bai 4 :tim so nguyen x va y biet: xy-x+2y=3
tim hai so nguyen duonga;b biet a/b=10/25 va BCNN(a;b)=100
cho a va b la 2 so nguyen duong ko chia nhet cho nhau biet BCNN a b la 630 UCLL a b la 18 tim hai so a b
Tim cac so nguyen duong a,b,c biet rang:a^3-b^3-c^3=3ab va a^2=2(b+c)
