\(2\sqrt x+1\sqrt x+3\\=3\sqrt x+3\) (đk: \(x\ge0\))
Ta thấy: \(\sqrt{x}\ge0\forall x\ge0\)
\(\Leftrightarrow3\sqrt{x}\ge0\forall x\ge0\)
\(\Leftrightarrow3\sqrt{x}+3\ge3\forall x\ge0\)
Dấu \("="\) xảy ra \(\Leftrightarrow3\sqrt{x}=0\Leftrightarrow x=0\left(tm\right)\)