\(B=2x^2+y^2-8x+2xy-4y+2025\)
\(=x^2+2xy+y^2-4x-4y+x^2-4x+2025\)
\(=\left(x+y\right)^2-4\left(x+y\right)+4+x^2-4x+4+2017\)
\(=\left(x+y-2\right)^2+\left(x-2\right)^2+2017\ge2017\forall x,y\)
Dấu '=' xảy ra khi \(\begin{cases}x-2=0\\ x+y-2=0\end{cases}\Rightarrow\begin{cases}x=2\\ y=-x+2=-2+2=0\end{cases}\)