\(A=\sum\left[\left(x+y\right)\sqrt{\frac{\left(y+z\right)\left(z+x\right)}{z^2}}\right]=\sum\left[\left(x+y\right)\sqrt{1+\frac{x+y}{z}+\frac{xy}{z^2}}\right]\ge_{AM-GM}\sum\left[\left(x+y\right)\sqrt{1+\frac{2\sqrt{xy}}{z}+\frac{xy}{z^2}}\right]=\sum\left[\left(x+y\right)\left(1+\frac{\sqrt{xy}}{z}\right)\right]=2\left(x+y+z\right)+\sum\frac{\left(x+y\right)\sqrt{xy}}{z}\ge_{AM-GM}2\left(x+y+z\right)+\sum\frac{2xy}{z}\ge2\left(x+y+z\right)+2\left(x+y+z\right)=4\left(x+y+z\right)=4\sqrt{2}\).