\(5x^2+y^2+4xy-14x-6y+2016=y^2+2y\left(2x-3\right)+5x^2-14x+2016\)
\(=y^2+2y\left(2x-3\right)+\left(4x^2-12x+9\right)+\left(x^2-2x+1\right)+2006\)
\(=y^2+2y\left(2x-3\right)+\left(2x-3\right)^2+\left(x-1\right)^2+2006\)
\(=\left(y+2x-3\right)^2+\left(x-1\right)^2+2006\ge2006\)
Dấu "=" xảy ra khi x=y=1