\(A=x^2+2x\)
\(=x^2+2.x.\frac{1}{2}+\frac{1}{4}-\frac{1}{4}\)
\(=\left(x+\frac{1}{4}\right)^2-\frac{1}{4}\ge\frac{-1}{4}\)
Min \(A=\frac{-1}{4}\Leftrightarrow x+\frac{1}{4}=0\Rightarrow x=-\frac{1}{4}\)
A = x2 +2x +1 -1 = (x+1)2 - 1
GTNN A = -1
( DỄ hơn ăn cơm sườn)