Question

tìm GTLN,GTNN: A=5+|1/3-x| B=2-|x+2/3|

Answer 1

\(A=5+\left|\dfrac{1}{3}-x\right|\ge5\forall x\)

Dấu '=' xảy ra khi \(x=\dfrac{1}{3}\)

\(B=2-\left|x+\dfrac{2}{3}\right|\le2\forall x\)

Dấu '=' xảy ra khi \(x=-\dfrac{2}{3}\)