\(A=\left|2x-1\right|+\left|2x-2019\right|=\left|2x-1\right|+\left|2019-2x\right|\)
\(\ge\left|2x-2x-1+2019\right|=2018\)
Dấu "=" xảy ra \(\Leftrightarrow\left(2x-1\right)\left(2019-2x\right)\ge0\).Tự giải tiếp.
\(A=\left|2x-1\right|+\left|2x-2019\right|=\left|2x-1\right|+\left|2019-2x\right|\)
\(\ge\left|2x-2x-1+2019\right|=2018\)
Dấu "=" xảy ra \(\Leftrightarrow\left(2x-1\right)\left(2019-2x\right)\ge0\).Tự giải tiếp.
a) tim gia tri nho nhat cua bieu thuc
A= | 2x-2 | + | 2x-2019 |
b) tim x lon nhat thoa man
| 2x-4 | - | 6-3x | = -1
Tim gia tri nho nhat cua cac bieu thuc sau:
a.(2x+1/3)^2-5/6
b.|2x-3|+|y-1/2|+3/4
Tim gia tri nho nhat cua bieu thuc \(Q=\frac{27-2x}{12-x}\)
tim gia tri nho nhat cua bieu thuc A=(x-1)+(x-2017)
gia tri nho nhat cua bieu thuc A = tri tuyet doi 2x - 13 - 7/4
Tim gia tri nho nhat cua bieu thuc :
A= 2|3x - 1|-1
tim gia tri nho nhat cua bieu thuc B=|x-2/3|-1
tim gia tri nho nhat cua bieu thuc A =(x)+(8-x)
tim gia tri nho nhat cua bieu thuc A=2022.Ix^2+1I+2023