a) \(A=-9x^2+12x+2\)
\(A=-9x^2+12x-4+6\)
\(A=6-\left(3x-2\right)^2\)
Có: \(\left(3x-2\right)^2\ge0\Rightarrow6-\left(3x-2\right)^2\le6\)
Dấu = xảy ra khi: \(\left(3x-2\right)^2=0\Rightarrow3x-2=0\Rightarrow x=\frac{2}{3}\)
Vậy: \(Max_A=6\) tại \(x=\frac{2}{3}\)