a; \(x\) - \(\dfrac{3}{5}\) = 1 - \(\dfrac{4}{5}\) + \(\dfrac{1}{6}\)
\(x\) - \(\dfrac{3}{5}\) = \(\dfrac{30}{30}\) - \(\dfrac{24}{30}\) + \(\dfrac{5}{30}\)
\(x\) - \(\dfrac{3}{5}\) = \(\dfrac{6}{30}\) + \(\dfrac{5}{30}\)
\(x\) - \(\dfrac{3}{5}\) = \(\dfrac{11}{30}\)
\(x\) = \(\dfrac{11}{30}\) + \(\dfrac{3}{5}\)
\(x\) = \(\dfrac{11}{30}\) + \(\dfrac{18}{30}\)
\(x\) = \(\dfrac{29}{30}\)
Vậy \(x\) = \(\dfrac{29}{30}\)
b; (- \(\dfrac{10}{4}\)) + \(\dfrac{1}{4}\) = \(\dfrac{3}{4}\) thế \(x\) của em đâu nhỉ???
c; - \(\dfrac{3}{2}\) + (\(x\) - \(\dfrac{1}{2}\)) = \(\dfrac{1}{2}\)
\(x\) - \(\dfrac{1}{2}\) = \(\dfrac{1}{2}\) + \(\dfrac{3}{2}\)
\(x\) - \(\dfrac{1}{2}\) = 2
\(x\) = 2 + \(\dfrac{1}{2}\)
\(x\) = \(\dfrac{4}{2}\) + \(\dfrac{1}{2}\)
\(x\) = \(\dfrac{5}{2}\)
Vậy \(x=\dfrac{5}{2}\)
d; \(x\) - \(\dfrac{2}{7}\) = \(\dfrac{7}{21}\)
\(x\) = \(\dfrac{7}{21}\) + \(\dfrac{2}{7}\)
\(x\) = \(\dfrac{7}{21}\) + \(\dfrac{6}{21}\)
\(x\) = \(\dfrac{13}{21}\)
Vậy \(x=\dfrac{13}{21}\)
đ; (\(\dfrac{1}{6}\) + \(\dfrac{1}{10}\) - \(\dfrac{1}{15}\)) + \(x\) = 0
(\(\dfrac{5}{30}\) + \(\dfrac{3}{30}\) - \(\dfrac{2}{30}\)) + \(x\) = 0
(\(\dfrac{8}{30}\) - \(\dfrac{2}{30}\)) + \(x\) = 0
\(\dfrac{1}{5}\) + \(x\) = 0
\(x\) = - \(\dfrac{1}{5}\)
Vậy \(x\) = - \(\dfrac{1}{5}\)