\(f\left(x\right)=x^2+2mx-4m+5\)
\(\text{Δ}=\left(2m\right)^2-4\cdot1\cdot\left(-4m+5\right)\)
\(=4m^2+16m-20\)
\(=4\left(m^2+4m-5\right)=4\left(m+5\right)\left(m-1\right)\)
Để f(x)>=0 với mọi x thuộc R thì \(\left\{{}\begin{matrix}\text{Δ}< =0\\1>0\left(đúng\right)\end{matrix}\right.\)
=>4(m+5)(m-1)<=0
=>(m+5)(m-1)<=0
=>-5<=m<=1