Question

TÌM CẶP SỐ NGUYÊN x,y thỏa mãn :

a, x^2 +y^2 -10x - 6y +34 =0 

Answer 1

\(x^2-2.5x+5^2+y^2-2.3y+3^2=0\)

\(\Leftrightarrow\left(x-5\right)^2+\left(y-3\right)^2=0\)

\(\Leftrightarrow\hept{\begin{cases}x=5\\y=3\end{cases}}\)

Answer 2

(x² - 10x + 25 ) +( y² - 6y+ 9 ) = 0

(x - 5)² +  ( y - 3 )²  =0

=> x =5

y = 3