a, \(\left(x+1\right)\left(y+3\right)=3\)
\(x+1;y+3\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\)
x + 1 | 1 | -1 | 3 | -3 |
y + 3 | 3 | -3 | 1 | -1 |
x | 0 | -2 | 2 | -4 |
y | 0 | -6 | -2 | -4 |
b, \(x^2-2xy=5\Rightarrow x\left(x-2y\right)=5\)
\(x;x-2y\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\)
x | 1 | -1 | 5 | -5 |
x - 2y | 5 | -5 | 1 | -1 |
y | -2 | 2 | 2 | -2 |