\(\dfrac{x}{3}\)=\(\dfrac{-11}{y}\)
⇒\(x.y\)\(=-11.3\)
\(x.y\)\(=-33\)
Ta có: \(-33=-1.33=33.-1=1.-33=-33.1=-11.3=-3.11=11.-3=3.-11\)
Vậy (\(x,y\))=\(\left(-1,33\right);\left(33,-1\right);\left(1,-33\right);\left(-33,1\right);\left(-11,3\right);\left(-3,11\right);\left(11,-3\right);\left(3,-11\right)\)