\(\frac{x}{3}-\frac{1}{y}=\frac{1}{6}\)
\(=>\frac{xy-3}{3y}=\frac{1}{6}\)
\(=>6xy-18=3y\)
\(=>6.\left(xy-3\right)=3y\)
\(=>xy-3=\frac{y}{2}\)
\(=>xy=\frac{y+6}{2}\)
\(=>xy.2=y+6\)
\(=>y.2x=y+6\)
Mình phân tích sai r ạ xl
Kham khảo 1 phần mêm :>>
\(\frac{x}{3}-\frac{1}{y}=\frac{1}{6}\)
\(3y=0\)
\(\frac{xy-3}{3y}=\frac{1}{6}\)
\(\frac{\left(2x-1\right)y-6}{6y}=0\)
\(\Rightarrow2x-1=0\)
\(\Rightarrow2x=1\Rightarrow x=\frac{1}{2}\)
\(\frac{1}{6y}=0\)
\(\Rightarrow2y=0\)
\(y=0\)
Vậy pt cs nghiệm là (x;y) = (1/2;0)
