\(\frac{x}{3}-\frac{1}{y}=\frac{2}{6}\)
\(\frac{xy}{3y}-\frac{3}{3y}=\frac{1}{3}\)
\(\frac{xy-3}{3y}=\frac{1}{3}\)
=> 3 ( xy - 3 ) = 3y
=> xy - 3 = 3y
=> y ( x - 3 ) = 3 = 1 . 3 = 3 . 1 = (-1) . (-3) = (-3) . (-1)
Lập bảng tính x, y là xong
Ta có: \(\frac{x}{3}-\frac{1}{y}=\frac{2}{6}-\frac{1}{3}\)
Quy đồng mẫu hai vế ta có:
\(\frac{x}{3}-\frac{1}{y}=\frac{1}{3}\)
\(\frac{x.y}{3.y}-\frac{1.3}{y.3}=\frac{1.y}{3.y}\)
\(\frac{x.y}{3y}-\frac{3}{3y}=\frac{y}{3y}\)
\(\frac{xy}{3y}-\frac{y}{3y}=\frac{3}{3y}\)
\(\frac{xy-y}{3y}=\frac{3}{3y}\)
\(\Rightarrow xy-y=3\)
\(y.\left(x-1\right)=3\) \(\left[3=1.3=\left(-1\right).\left(-3\right)\right]\)
Vậy x = 4 thì y = 1.
x = 2 thì y = 3
x = -2 thì y = -1
x = 0 thì y = -3
X/3 - 1/Y = 2/6
Cách 1 : TA CÓ Cách 2 : ta có
X/Y-1/3=2/6 1/3 - X/Y=2/6
X/Y=2/6+1/3 X/Y =1/3-2/6
X/Y=2/3 X/Y = 0/3
Ta có x , y ∈ Z : x/3 - 1/y = 2/6 .
=> x/3 - 2/6 = 1/y .
=> 2x/6 - 2/6 = 1/y .
=> ( 2x - 2 ) / 6 = 1/y .
=> ( 2x - 2 ) * y = 6 .
=> 6 ⋮ 2x - 2 ; ⋮ y .
=> 2x - 2 ; y ∈ Ư ( 6 ) = { -6 ; -3 ; -2 ; -1 ; 1 ; 2 ; 3 ; 6 } .
Vì 2x - 2 ⋮ 2 nên 2x - 2 = -6 ; -2 ; 2 ; 6 .
=> 2x = -4 ; 0 ; 4 ; 8 .
=> x = -2 ; 0 ; 2 ; 4 .
Do đó y = -1 ; -3 ; 3 ; 1 .
Vậy x = -2 ; y = -1 .
x = 0 ; y = -3 .
x = 2 ; y = 3 .
x = 4 ; y = 1 .