Ta có: (x-1)(x+2)(x-3)=0
\(\Rightarrow\left[{}\begin{matrix}x-1=0\\x+2=0\\x-3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-2\\x=3\end{matrix}\right.\)
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\(\left(x-1\right)\left(x+2\right)\left(x-3\right)=0\)
⇔\(x-1=0\) \(hay\) \(x+2=0\) \(hay\) \(x-3=0\)
⇔\(x=1\) \(hay\) \(x=-2\) \(hay\) \(x=3\)
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