\(2abc:17=abc\)
\(\Rightarrow\left(2000+abc\right):17=abc\)
\(\Rightarrow2000:abc+1=17\)
\(\Rightarrow2000:abc=16\)
\(\Rightarrow abc=2000:16=125\)
Ta có:
2000+abc=16.abc+abc
=>abc.16=2000
abc=2000:16
abc=125
chúc bạn học tốt nha
\(\text{ Ta có : }\)
\(2abc\text{ : }17=abc\)
\(2000+abc=16\cdot abc+abc\)
\(\Leftrightarrow abc\cdot16=2000\)
\(abc=2000\text{ : }16\)
\(abc=125\)
\(\Rightarrow a=1\)
\(\Rightarrow b=2\)
\(\Rightarrow c=5\)