Question

Tìm b∈Z sao cho:

6b+35 là bội số của b+3

Answer 1

\(\Rightarrow6\left(b+3\right)+17⋮b+3\\ \Rightarrow b+3\inƯ\left(17\right)=\left\{-17;-1;1;17\right\}\\ \Rightarrow b\in\left\{-21;-4;-2;14\right\}\)

Answer 2

\(6b+35⋮b+3\\ \Rightarrow6b+35⋮6b+18\\ \Rightarrow\left(6b+35\right)-\left(6b+18\right)⋮b+3\\ \Rightarrow17⋮b+3\\ \Rightarrow b+3\inƯ\left(17\right)=\left\{\pm17;\pm1\right\}\)

\(b+3\)	\(17\)	\(1\)	\(-1\)	\(-17\)
\(b\)	\(14\)	\(-2\)	\(-4\)	\(-20\)