1) Ta có: 10 = 2.5
12 = 22.3
15 = 3.5
=> BCNN(10;12;15) = 22.3.5 = 60
2) Do 8;9;11 nguyên tố cùng nhau từng đôi một => BCNN(8;9;11) = 8.9.11 = 792
3) Ta có: 24 = 23.3
40 = 23.5
168 = 23.3.7
=> BCNN(24;40;168) = 23.3.5.7 = 840
BCNN(10,12,15) là:
10=2.5
12=22.3
15=3.5
=>BCNN(10,12,15)=22.3.5=60
BCNN(8,9,11):
8=23
9=32
11=11
=>BCNN(8,9,11)=23.32.11=792
BCNN(24,40,168):
24=23.3
40=23.5
168=23.3.7
=> BCNN(24;40;168)=23.3.5.7=840
BCNN(10,12,15) là:
10=2.5
12=22.3
15=3.5
=>BCNN(10,12,15)=22.3.5=60
BCNN(8,9,11):
8=23
9=32
11=11
=>BCNN(8,9,11)=23.32.11=792
BCNN(24,40,168):
24=23.3
40=23.5
168=23.3.7
=> BCNN(24;40;168)=23.3.5.7=840
BCNN(10,12,15) là:
10=2.5
12=22.3
15=3.5
=>BCNN(10,12,15)=22.3.5=60
BCNN(8,9,11):
8=23
9=32
11=11
=>BCNN(8,9,11)=23.32.11=792
BCNN(24,40,168):
24=23.3
40=23.5
168=23.3.7
=> BCNN(24;40;168)=23.3.5.7=840
BCNN(10,12,15) là:
10=2.5
12=22.3
15=3.5
=>BCNN(10,12,15)=22.3.5=60
BCNN(8,9,11):
8=23
9=32
11=11
=>BCNN(8,9,11)=23.32.11=792
BCNN(24,40,168):
24=23.3
40=23.5
168=23.3.7
=> BCNN(24;40;168)=23.3.5.7=840
) Ta có: 10 = 2.5
12 = 22.3
15 = 3.5
=> BCNN(10;12;15) = 22.3.5 = 60
2) Do 8;9;11 nguyên tố cùng nhau từng đôi một => BCNN(8;9;11) = 8.9.11 = 792
3) Ta có: 24 = 23.3
40 = 23.5
168 = 23.3.7
=> BCNN(24;40;168) = 23.3.5.7 = 84
ta co : 10 = 2.5
12 = 2.2 . 3
15 =3.5
= > bcnn [10;12;15]
2] do