a2+b2+c2+4 <= ab+3b+2c
<=>a2+b2+c2+4-ab-3b-2c<=0
<=>a2-2*a*1/2*b+(1/2*b)2+3/4*(b2-4b+4)+c2-2c+1<=0
<=>(a-1/2*b)2+3/4*(b-2)2+(c-1)2<=0
Mả (a-1/2*b)2 =>0
3/4*(b-2)2=>0
(c-1)2=>0
Suy ra:a-1/2*b=0.Suyra a=1/2*b
b-2=0 .Suy ra b=2
c-1=0. Suy ra c=1
Vay a=1 ; b=2 ; c=1