Ta có : abc x 9 = 4abc
=> abc x 9 = 4000 + abc
=> abc x 9 - abc = 4000
=> abc x (9 - 1) = 4000
=> abc x 8 = 4000
=> abc = 4000 : 8
=> abc = 500
Vậy abc = 500
Ta có:\(\overline{abc}\times9=\overline{4abc}\)
\(\overline{abc}\times9=4000+\overline{abc}\)
\(\overline{abc}\times8=4000\)
\(\overline{abc}=4000:8=500\)
\(9abc=4abc\)
\(9abc-4abc=0\)
\(5abc=0\)
\(abc=\frac{0}{5}=0\)
\(9abc=4abc\)
\(9abc-4abc=0\)
\(5abc=0\)
\(abc=\frac{5}{0}=0\)
~Study well~:)
Theo bài ra , ta có :
abc x 9 = 4abc
abc x 9 = 4000 + abc
abc x 9 - abc = 4000
abc x ( 9 - 1 ) = 4000
abc x 8 = 4000
abc = 4000 : 8
abc = 500
\(Taco:\overline{abc}.9=\overline{4abc}\)
\(\overline{abc}.9=4000+\overline{abc}\)
\(\overline{abc}.9-\overline{abc}=4000\)
\(\overline{abc}.\left(9-1\right)=4000\)
\(\overline{abc}.8=4000\)
\(\overline{abc}=4000:8\)
\(\Rightarrow\overline{abc}=500\)
