4ab . 2 = ab8 => 2(400 + ab) = 10.ab + 8 <=> 800 + 2.ab = 10.ab + 8 => 792 = 8.ab => ab = 792 : 8 = 99
Tìm ab biết : 4ab x 2 = ab8
4ab . 2 = ab8
(400+ab) x 2 = ab x 10 +8
800 - 8 = ab x 10 - ab x2
ab x 8 = 792
ab = 792 : 8
ab = 99
Vậy a = 9 , b = 9
Ta có:
4ab x 2 = ab8
=> (400 + ab) x 2 = ab x 10 + 8
=> 400 x 2 + ab x 2 = ab x 10 + 8
=> 800 + ab x 2 = ab x 10 + 8
=> ab x 10 - ab x 2 = 800 - 8
=> ab x 8 = 792
=> ab = 792 : 8 = 99
4ab . 2 = ab8
(400+ab) x 2 = ab x 10 +8
800 + ab x 2 = ab x 10 +8
800 - 8 = ab x 10 - ab x2
ab x 8 = 792
ab = 792 : 8
ab = 99
Vậy a = 9 , b = 9
4ab x 2 = ab8
( 400 + ab ) x 2 = ab x 10 + 8
800 + ab x 2 = ab x 10 + 8
792 = ab x 8
792 : 8 = ab
99 =ab
