2xyz+4xyz-\(\frac{1}{2}\) xyz
=(2+4-\(\frac{1}{2}\) )(xxxyyyzzz)
=3.5x3 y3z3
2xyz+4xyz-\(\frac{1}{2}\) xyz
=(2+4-\(\frac{1}{2}\) )(xxxyyyzzz)
=3.5x3 y3z3
thuc hien phep tinh:
a,\(1\dfrac{1}{2}\). \(2\dfrac{1}{3}\)+ \(1\dfrac{1}{3}\). \(\dfrac{1}{2}\)
b,\(\dfrac{1}{9}\).\(\dfrac{2}{145}\)\(-4\dfrac{1}{3}\). \(\dfrac{2}{145}\)+\(\dfrac{2}{145}\)
Tìm x,y,z biết: \(\dfrac{4}{x+1} =\dfrac{2}{y-2}=\dfrac{3}{z+2} \) và \(xyz=12\)
tìm x,y,z:
\(\dfrac{4}{x+1}=\dfrac{z}{y-2}=\dfrac{3}{z+2}\) và xyz=12
1.tìm số xyz biết \(\dfrac{x^2}{4}=\dfrac{y^2}{9}=\dfrac{z^2}{25},vàx-y+z=4\)
2. biết \(a^2+ab+\dfrac{b^2}{3}=25;c^2+\dfrac{b^2}{3}=9;a^2+ac+c^2=16\) và a≠ 0; c ≠ 0; a ≠ -0. c/m rằng \(\dfrac{2c}{a}=\dfrac{b+c}{a+c}\)
tính tổng và hiệu của các dơn thức
a.-\(\dfrac{1}{3}\)\(\times\)\(x\)3y1và\(\dfrac{4}{3}\)\(\times\)\(\chi\)3y4
b.-2xyz và xyz
Tìm x, biết
a)\(\dfrac{1}{2}\)x\(x\)-\(\dfrac{7}{3}\)=\(\dfrac{-5}{6}\)+\(\dfrac{3}{4}\)x\(x\)
b)\(\dfrac{4}{5}\)x\(x\)-\(\dfrac{6}{5}\)=\(\dfrac{1}{2}\)+\(\dfrac{3}{2}\)x\(x\)
c)\(\dfrac{2}{5}\)x(3x\(x\)+\(\dfrac{3}{4}\))=\(1\dfrac{1}{5}\)-\(\dfrac{1}{3}\)x\(x\)
d)2x(3x\(x \)+\(\dfrac{3}{4}\))+\(\dfrac{4}{5}\)=\(\dfrac{1}{2}\)-2x\(x\)
Tìm x:
a) \(\dfrac{11}{12}\) - (\(\dfrac{2}{5}\) + \(\dfrac{3}{4}\)x) \(\dfrac{2}{3}\)
b) \(\dfrac{-2}{5}\) + \(\dfrac{5}{3}\) . (\(\dfrac{3}{2}\) - \(\dfrac{4}{15}\)x) = \(\dfrac{-7}{6}\)
c) \(\dfrac{1}{2}\) + \(\dfrac{3}{4}\)x = \(\dfrac{1}{4}\)
bài 1
a.\(\dfrac{16}{4}.x=\dfrac{16}{2}\)
b.\(2xy^3+4x^2y+8xy^3-1x^2y\)
c.\(15x+3xyz^3-4xy^2-14x+2xyz^3+xy^2\)
giúp me vứi
Tìm số nguyên x, biết:
a) \(-4\dfrac{3}{5}\). \(2\dfrac{4}{3}\) < x < \(-2\dfrac{3}{5}\) : \(1\dfrac{6}{15}\)
b) \(-4\dfrac{1}{3}\).(\(\dfrac{1}{2}\)-\(\dfrac{1}{6}\)) < x < - \(\dfrac{2}{3}\).(\(\dfrac{1}{3}\) - \(\dfrac{1}{2}\) - \(\dfrac{3}{4}\))