Question

thuc hien phep tinh:

a,\(1\dfrac{1}{2}\). \(2\dfrac{1}{3}\)+ \(1\dfrac{1}{3}\). \(\dfrac{1}{2}\)

b,\(\dfrac{1}{9}\).\(\dfrac{2}{145}\)\(-4\dfrac{1}{3}\). \(\dfrac{2}{145}\)+\(\dfrac{2}{145}\)

Answer 1

a,9 phần 2

Answer 2

b)\(\frac{1}{9}.\frac{2}{145}-4\frac{1}{3}.\frac{2}{145}+\frac{2}{145}\)

\(=\frac{2}{145}.\left(\frac{1}{9}-\frac{13}{3}+1\right)\)

\(=\frac{2}{145}.\left(-\frac{29}{9}\right)\)

\(=\frac{-2}{45}\)

Answer 3

9/2 nha

Answer 4

a)\(1\frac{1}{2}.2\frac{1}{3}+1\frac{1}{3}.\frac{1}{2}\)

=\(=\frac{3}{2}.\frac{7}{3}+\frac{4}{3}.\frac{1}{2}\)

\(=\frac{7}{2}+\frac{2}{3}\)

\(=\frac{25}{6}\)