Question

thực hiện phép tính sau:

Answer 1

\(\dfrac{2\left(2x+3y\right)}{x-1}.\dfrac{\left(x-1\right)\left(x^2+x+1\right)}{\left(2x+3y\right)^2}=\dfrac{2\left(x^2+x+1\right)}{2x+3y}\)