Ta có: C = a (b + c) - b (a - c) - c (a + b) + 3 ac
= ab + ac - ba + bc - ca - cb + 3 ac
= (ab - ba) + (ac - ca) + (bc - cb) + 3 ac
= 0 + 0 + 0 + 3 ac
= 3 ac
Ta có:
C = a ( b + c ) - b ( a - c ) - c ( a + b ) + 3ac
C = ab + ac - ba + bc - ca - cb + 3ac
C = ( ab - ba ) + ( ac - ca ) + ( bc - cb ) + 3ac
C = 0 + 0 + 0 + 3ac
C = 3ac