ĐKXĐ: x+1>=0
=>x>=-1
\(\sqrt{x+1}=11\)
=>\(x+1=11^2=121\)
=>x=121-1=120(nhận)
ĐKXĐ: x+1>=0
=>x>=-1
\(\sqrt{x+1}=11\)
=>\(x+1=11^2=121\)
=>x=121-1=120(nhận)
Tính nhanh:
\(\frac{3-3^2+3^3-3^4+...+3^{99}}{\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^{99}}}.\left(11-\sqrt{91}\right)\left(11-\sqrt{95}\right)\left(11+\sqrt{99}\right)\left(11-\sqrt{103}\right)\left(11-\sqrt{109}\right)\left(11-\sqrt{113}\right)...\left(11-\sqrt{113}\right)\left(11-\sqrt{104}\right)\)
\(\dfrac{1}{5}+\dfrac{11}{10}:\sqrt{x}=\dfrac{3}{4}\)
Bài 1: Tìm x; y ϵ \(ℤ\)
a) 2x - y\(\sqrt{6}\) = 5 + (x + 1)\(\sqrt{6}\)
b) 5x + y - (2x -1)\(\sqrt{7}\) = y\(\sqrt{7}\) + 2
Bài 2: So sánh M và N
M = \(\dfrac{\dfrac{3}{4}+\dfrac{3}{5}+\dfrac{3}{7}-\dfrac{3}{11}}{\dfrac{6}{4}+\dfrac{6}{5}+\dfrac{6}{7}-\dfrac{6}{11}}\)
N = \(\dfrac{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}{\dfrac{6}{2}+\dfrac{6}{5}-\dfrac{6}{7}-\dfrac{6}{11}}\)
Bài 3: Chứng minh:
\(\dfrac{1}{2!}+\dfrac{1}{3!}+\dfrac{1}{4!}+...+\dfrac{1}{2023!}< 1\)
bài 1: tìm x, biết:
a)\(\sqrt{x}\)=7
b)\(\sqrt{x+1}\)=11
c)\(\sqrt{x-3}\)=13
d)\(\sqrt{3x+4}\)=5
e)\(\sqrt{3x+\frac{1}{2}}\)\(-\frac{3}{2}\)=0
bai1 tim x
1)\(\sqrt{x}=1\)
2)\(\sqrt{x}=3\)
3)\(\sqrt{x+1}=11\)
4)\(\sqrt{x-2}=12\)
5)\(\sqrt{2-3x}=9\)
6)\(\sqrt{3x+4}=5\)
cac bạn nhớ làm giup minh voi mai minh kiem tra mon toan roi
tìm số x dương biết
a)\(\frac{5}{11}.\sqrt{x}-\frac{1}{3}=\frac{1}{6}\)
b)\(\sqrt{x+1}-2=0\)
nhanh lên nha mn, tl trước 5h nha..
Tìm x:
a) 3- \(\sqrt{x}\)=0
b) 2\(\sqrt{x}\)-1=27
c) \(\frac{5}{11}\)\(\sqrt{x}\)-\(\frac{1}{3}\)=\(\frac{1}{6}\)
Tìm số x không âm biết:
a,3-\(\sqrt{x=0}\) b,\(2\sqrt{x-1=27}\) c\(\frac{5}{11}\sqrt{x-\frac{1}{3}}=\frac{1}{6}\)
tìm x( x bé hơn hoặc bằng 0)
a) \(\sqrt{x}=0\)
b)\(\sqrt{x}=3\)
c)\(\sqrt{x}=2\)
d)\(\sqrt{x+11}=11\)
e)\(\sqrt{x-7}=17\)
f)\(\sqrt{19-x}=19\)
Giúp mik vs!
So sánh x và y
1) x = \(2\sqrt{7}\);y = \(3\sqrt{3}\)
2) x = \(6\sqrt{2}\);y= \(5\sqrt{3}\)
3) x= \(\sqrt{31}\)- \(\sqrt{13}\); y = 6- \(\sqrt{11}\)