=>căn x-2=4-2x
=>x-2=(4-2x)^2 và x<=2
=>x=2
Tìm x, biết:
5/x+y/4=1/8
A=\(\frac{\sqrt{2}+1}{\sqrt{x}-3}\)(x>=0)
2.|5x-3|-2x=14
x-\(2\sqrt{2}\)=0(x>=0)
Tìm x, biết:
\(\dfrac{1}{2}x+\dfrac{4}{5}=2x-\dfrac{8}{5}\)
\(\sqrt{x}=5\) (x ≥ 0)
x2 = 3
a]\(\sqrt{0,04}\)-x=7
b] x2=36
c] 2x2 =10
d]x2-2=0
e](x-1)2=4
f](2x+1)2=49
g]\(\sqrt{x}\).(x2-1)=0
k]\(\sqrt[2]{x+1-3=5}\)
Cho x,y,z thỏa mãn đồng thời: \(3x-2y-2\sqrt{y+2012}+1=0\); \(3y-2z-2\sqrt{z-2013}+1=0\);\(3z-2x-2\sqrt{x-2}-2=0\)Tính \(C=\left(x-4\right)^{2016}+\left(y+2012\right)^{2017}+\left(z-2013\right)^{2008}\)
a. |\(\frac{x}{3}\)-1| + (2x - 6)2 + \(\sqrt{x-3}\)=0
b. 2 x \(\sqrt{x}\) - 3 = 4
\(2\left|2x-6\right|=\dfrac{5}{6}-\left|x-3\right|\)
2:\(\left|x+2013\right|+\left|x+2014\right|+\left|x+2045\right|=2\)
3:\(\left|2x-1\right|=\left|x+1\right|\)
4:\(\sqrt{\left(x+\sqrt{5}\right)}+\sqrt{\left(y-\sqrt{3}\right)^2}+\left|x-y-z\right|=0\)
Bài 1: Tìm x, biết:
a) \(\sqrt{1,69}.(2.\sqrt{x}+\sqrt{81/121})=13/10\)
b) \((2x^2-3).(3x^2-1/0,12).(x^2+1)=0\)
c) \(|2/5.\sqrt{x}-1/20|-3/4=1/5\)
d) \(x-5\sqrt{x}=0\)
e) \(2x^7=3x^9\)
f) \(x^6=4x^8\)
Giải hộ mik với nha! Thank you
Bài 1:
a)2x-\(\sqrt{_{ }}\)căn 2=0
b)|x+1|+|x+5|+|x+7|=105x
Bài 2
Tìm x,y,z
2x-4y/12=4z-3x/2=3y-2z/4-biết 2x-y+z=27
Tìm x
a, \(\sqrt{x}=2\)
b, \(\sqrt{x-1-5}=0\)
c, \(3\sqrt{2x5+7}=0\)
d, \(\sqrt{\left(2x+1\right)^2-x}=4\)
72x+72x+3=344 (5-x)(9x2-4)=0 \(\left|2-2x\right|\)-3,75=(-0,5)2
\(\sqrt{x-1}\)+\(\dfrac{2}{3}\)=1 (\(\dfrac{1}{3}\)-\(\dfrac{3}{2}\)x)2=2\(\dfrac{1}{4}\) giúp mình với!!!! cảm ơn nhìu=))❤
