giải phương trình
1)\(\sqrt{9\left(x-1\right)}=21\)
2)\(\sqrt{1-x}+\sqrt{4-4x}-\dfrac{1}{3}\sqrt{16-16x}+5=0\)
3)\(\sqrt{2x}-\sqrt{50}=0\)
4)\(\sqrt{4x^2+4x+1}=6\)
5)\(\sqrt{\left(x-3\right)^2}=3-x\)
giải phương trình
a)\(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}+2=0\)
b)\(\sqrt{16x+16}-\sqrt{9x+9}+\sqrt{4x+4}+\sqrt{x+1}=16\)
c)\(\sqrt{4x+20}+\sqrt{x+5}-\dfrac{1}{3}\sqrt{9x+45}=4\)
d)\(\dfrac{1}{3}\sqrt{2x}-\sqrt{8x}+\sqrt{18x}-10=2\)
\(\sqrt{25x+25}-\sqrt{16x+16}+\sqrt{9x+9}-\sqrt{4x+4}+\sqrt{x+1}=27\)
a \(\sqrt{4x-20}+\sqrt{x-5}-\dfrac{1}{3}\sqrt{9x-45}=4\)
b \(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}=4\)
c \(\dfrac{1}{3}\sqrt{x-2}-\dfrac{2}{3}\sqrt{9x-18}+6\sqrt{\dfrac{x-2}{81}=-4}\)
d \(\sqrt{9x+27}+4\sqrt{x+3}-\dfrac{3}{4}\sqrt{16x+48}=0\)
1 Giaỉ các phương trình sau ;
a)\(\sqrt[]{4x^2-4x+9=3}\) b) \(\sqrt[]{16x=8}\)
c) \(\sqrt{2x}=\sqrt{5}\) d) \(\sqrt[]{3x-1}=4\)
e)\(\sqrt[]{4\left(1-x\right)^2}-6=0\) g) \(\sqrt[]{x^2-x+16=4}\)
mn giúp e nha , e đang cần gấp ^^
a.\(\sqrt{16x}\) =8
b.\(\sqrt{4x}\) =\(\sqrt{5}\)
c.\(\sqrt{\left(x-1\right)}\) =21
giúp mình với
a) \(\sqrt{4x^2-9}=2\sqrt{x+3}\)
b) \(\sqrt{4x+20}+3\sqrt{\dfrac{x-5}{9}}-\dfrac{1}{3}\sqrt{9x-45}=4\)
c) \(\dfrac{2}{3}\sqrt{9x-9}-\dfrac{1}{4}\sqrt{16x-16}+27\sqrt{\dfrac{x-1}{81}}=4\)
d)\(5\sqrt{\dfrac{9x-27}{25}}-7\sqrt{\dfrac{4x-12}{9}}-7\sqrt{x^2-9}+18\sqrt{\dfrac{9x^2-81}{81}}=0\)
Giải phương trình:
1: \(\left(x^2+2\right)^2+4\left(x+1\right)^3+\sqrt{x^2+2x+5}=\left(2x-1\right)^2+2\)
2: \(\left(13-4x\right)\sqrt{2x-3}+\left(4x-3\right)\sqrt{5-2x}=2+8\sqrt{16x-4x^2-15}\)
Bài 1 : Giải các phương trình sau:
a)\(\sqrt{2x+1}=2\)
b)\(\sqrt{3x}-1=4\)
c)\(\sqrt{16x^2}=12\)
d)\(\sqrt{x^2-4x+4}=1\)
e)\(3\sqrt{x}-2\sqrt{9x}+\sqrt{16x}=5\)
f)\(4\sqrt{3x}-\sqrt{12x}+5\sqrt{27x}=17\)
g)\(4\sqrt{x-5}-\sqrt{4x-20}+\sqrt{16x-80}=2\)
h)\(2\sqrt{x-1}+\sqrt{4x-4}-\sqrt{9x-9}=2\)
i)\(-\sqrt{x+2}-\sqrt{4x+8}-\sqrt{9x+18}=-\sqrt{x+5}\)
k)\(\sqrt{2-x}=\sqrt{x+5}\)
l)\(\sqrt{2-x}=\sqrt{4+x}\)
m)\(x+\sqrt{4x-3}=2\)
n)\(\sqrt{4x^2-4x+1}=\sqrt{\left(x+2\right)^2}\)
o)\(\sqrt{x^2-2x+1}-\sqrt{x^2-6x+9}=0\)