\(A=\sqrt{4-\sqrt{7}+\sqrt{4+\sqrt{7}}-}\sqrt{14}\)=> \(\sqrt{2}A=\sqrt{7-2\sqrt{7}+1}+\sqrt{7+2\sqrt{7}+1}-2\sqrt{7}=\sqrt{7}-1+\sqrt{7+1-2\sqrt{7}=0}\)=> A=0
Tính
\(\sqrt{7-2\sqrt{10}}\) - \(\sqrt{14+4\sqrt{10}}\) - \(2\sqrt{2x-4\sqrt{10}}\) + 3\(\sqrt{13-4\sqrt{10}}\)
1/ \(\frac{2}{3-\sqrt{7}}\sqrt{\frac{6\sqrt{2}-2\sqrt{14}}{3\sqrt{2}+\sqrt{14}}}\)
2/ \(\sqrt{6+2\sqrt{\sqrt{5}-\sqrt{13-\sqrt{48}}}}\)
3/ \(\frac{\sqrt{3-2\sqrt{2}}}{\sqrt{17-12\sqrt{2}}}-\frac{\sqrt{3+2\sqrt{2}}}{\sqrt{17+12\sqrt{2}}}\)
4/ \(\frac{24}{\sqrt{7}+1}+\frac{4}{3+\sqrt{7}}-\frac{3}{\sqrt{7}+2}\left(4-\sqrt{7}\right)\)
5/ \(\sqrt{7-3\sqrt{5}}\left(7+3\sqrt{5}\right)\left(3\sqrt{2}+\sqrt{10}\right)\)
1)Tìm x để căn thức sau có nghĩa
a)\(\sqrt{2x-4}\) b)\(\sqrt{\dfrac{-7}{4-x}}\)
2) Tính
A=\(\sqrt{9+4\sqrt{5}}-\sqrt{9-4\sqrt{5}}
\)
B=\(\left(\dfrac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}+\dfrac{\sqrt{15}-\sqrt{5}}{1-\sqrt{3}}\right):\dfrac{1}{\sqrt{7}-\sqrt{5}}\)
Helpppp
Tính:
1) \(\sqrt{4-2\sqrt{3}}\)
2) \(\sqrt{5+2\sqrt{6}}\)
3) \(\sqrt{7-2\sqrt{10}}\)
4) \(\sqrt{14-6\sqrt{6}}\)
5) \(\sqrt{8+2\sqrt{15}}\)
6) \(\sqrt{10-2\sqrt{21}}\)
7) \(\sqrt{11+2\sqrt{18}}\)
LÀM CHI TIẾT GIÚP MK NHÉ!
Rút gọn
a) A=\(\sqrt{14+6\sqrt{5}}+\sqrt{14-6\sqrt{5}}\)
b)B=\(\sqrt{7-4\sqrt{3}}-\sqrt{7+4\sqrt{3}}\)
Giúp e với ạ
Tính:
1) \(\sqrt{14-2\sqrt{33}}\)
2) \(\sqrt{12-2\sqrt{35}}\)
3) \(\sqrt{16-2\sqrt{55}}\)
4) \(\sqrt{14-6\sqrt{5}}\)
5) \(\sqrt{17-12\sqrt{2}}\)
6) \(\sqrt{27-12\sqrt{5}}\)
7) \(\sqrt{4+\sqrt{15}}\)
LÀM CHI TIẾT GIÚP MK NHÉ!
1) Rut gon bieu thuc A = \(\left(4+\sqrt{7}\right).\left(\sqrt{2}-\sqrt{14}\right).\sqrt{4-\sqrt{7}}\)
tính
a.\(\sqrt{3+2\sqrt{2}}\)
b.\(\sqrt{7+4\sqrt{3}}\)
c. \(\sqrt{14-6\sqrt{5}}\)
B 5. Rút gọn các biểu thức sau:
a)\(\sqrt{7+4\sqrt{3}}\) b)\(\sqrt{9-4\sqrt{5}}\)
c)\(\sqrt{14+6\sqrt{5}}\) d)\(\sqrt{17-12\sqrt{2}}\)
