\(\sqrt{16-2\sqrt{55}}=\sqrt{5-2\sqrt{5}\sqrt{11}+11}\) \(=\sqrt{\left(\sqrt{5}-\sqrt{11}\right)^2}=\sqrt{5}-\sqrt{11}\)
\(\sqrt{16-2\sqrt{55}}=\sqrt{\left(\sqrt{11}-\sqrt{5}\right)}=\left|\sqrt{11}-\sqrt{5}\right|=\sqrt{11}-\sqrt{5}\)
\(\sqrt{16-2\sqrt{55}}=\sqrt{5-2\sqrt{5}\sqrt{11}+11}\) \(=\sqrt{\left(\sqrt{5}-\sqrt{11}\right)^2}=\sqrt{5}-\sqrt{11}\)
\(\sqrt{16-2\sqrt{55}}=\sqrt{\left(\sqrt{11}-\sqrt{5}\right)}=\left|\sqrt{11}-\sqrt{5}\right|=\sqrt{11}-\sqrt{5}\)
Nếu \(\sqrt{16-2\sqrt{55}}\) = \(\sqrt{a}-\sqrt{b}\), với a,b ∈Z thì a − b = ......
Tính:
1) \(\sqrt{14-2\sqrt{33}}\)
2) \(\sqrt{12-2\sqrt{35}}\)
3) \(\sqrt{16-2\sqrt{55}}\)
4) \(\sqrt{14-6\sqrt{5}}\)
5) \(\sqrt{17-12\sqrt{2}}\)
6) \(\sqrt{27-12\sqrt{5}}\)
7) \(\sqrt{4+\sqrt{15}}\)
LÀM CHI TIẾT GIÚP MK NHÉ!
Cho \(\sqrt{16-2\sqrt{55}}=\sqrt{a}-\sqrt{b}\) . Tính a-b
nếu \(\sqrt{16-2\sqrt{55}}=\sqrt{a}-\sqrt{b}\) với \(a,b\in Z\) thì a+b=?
\(\sqrt{16-2\sqrt{55}}\) = \(\sqrt{a}\) - \(\sqrt{b}\) với a, b thuộc Z thì a - b= ?
\(\sqrt{11+2\sqrt{18}}\)
\(\sqrt{7+2\sqrt{10}}\)
\(\sqrt{7+4\sqrt{3}}\)
\(\sqrt{12-2\sqrt{55}}\)
Tính:
a) \(\sqrt{7}.\sqrt{55}.\sqrt{35}.\sqrt{11}\)
b) \(\frac{\sqrt{144}}{23}:\frac{\sqrt{16}}{23}\)
c) \(\frac{\sqrt{5}}{\sqrt{125}}\)
d) \(\frac{\sqrt{135}}{\sqrt{15}}\)
Tính giá trị P=\(\frac{a^3-3a+2}{a^3-4a^2+5a-2}\)
biết \(a=\sqrt[3]{55+\sqrt{3024}}+\sqrt[3]{55-\sqrt{3024}}\)
Rút gọn
\(\sqrt{5+\sqrt{21}}+\sqrt{5-\sqrt{21}}-2\sqrt{4\sqrt{7}}\)\(\sqrt{8+\sqrt{55}}-\sqrt{8-\sqrt{55}}-\sqrt{125}\)\(\left(\sqrt{14}-\sqrt{10}\right)\left(6-\sqrt{35}\right)\sqrt{6+\sqrt{35}}\)\(\left(\sqrt{2}+1\right)\left(\sqrt{3}-1\right)\left(\sqrt{6}+1\right)\left(5-2\sqrt{2}-\sqrt{3}\right)\)\(\sqrt{7-3\sqrt{5}}\left(7+3\sqrt{5}\right)\left(3\sqrt{2}+\sqrt{10}\right)\)