mình cần giải ra chứ hk cần kq thks bn
\(\sqrt{14+8\sqrt{3}}=\sqrt{\left(\sqrt{6}+\sqrt{8}\right)^2}=\left|\sqrt{6}+2\sqrt{2}\right|=\sqrt{6}+2\sqrt{2}\)
\(\sqrt{14+8\sqrt{3}}=\sqrt{8+2\cdot2\sqrt{2}\cdot\sqrt{6}+6}=\sqrt{\left(2\sqrt{2}\right)^2+2\cdot2\sqrt{2}\cdot\sqrt{6}+\left(\sqrt{6}\right)^2}=\)
\(=\sqrt{\left(2\sqrt{3}+\sqrt{6}\right)^2}=2\sqrt{3}+\sqrt{6}\)