Ta có:
\(A=\frac{2^{23}+1}{2^{25}+1}\Rightarrow2A=\frac{2^{25}+2}{2^{25}+1}=1+\frac{1}{2^{25}+1}\)
\(B=\frac{2^{25}+1}{2^{27}+1}\Rightarrow2B=\frac{2^{27}+2}{2^{27}+1}=1+\frac{1}{2^{27}+1}\)
\(\frac{1}{2^{25}+1}>\frac{1}{2^{27}+1}\Rightarrow2A>2B\Rightarrow A>B\)
so sánh
x=\(\frac{2^{23}+1}{2^{25}+1}\)và y=\(\frac{2^{25}+1}{2^{27}+1}\)
Giúp tớ bài này nhé !
SO SÁNH:
\(\frac{2^{23}+1}{2^{25}+1}\)và\(\frac{2^{25}+1}{2^{27}+1}\)
So sánh: \(\frac{2^{23}+1}{2^{25}+1}\) và \(\frac{2^{25}+1}{2^{27}+1}\)
s0 sanh
\(\frac{2^{23}+1}{2^{25}+1}\) vs \(\frac{2^{25}+1}{2^{27}+1}\)
So sánh: 2^23+1/2^25+1 và 2^25+1/2^27+1
- Thực hiện phép tính :
a)\(5\frac{27}{5}+\frac{27}{23}+0,5-\frac{5}{27}+\frac{16}{23}
\)
b) \(\frac{3}{8}.27\frac{1}{5}-51\frac{1}{5}.\frac{3}{8}+19\)
c) 25.\(\left(\frac{-1}{5}\right)^3+\frac{1}{5}-2.\left(\frac{-1}{2}\right)^2-\frac{1}{2}\)
d) \(35\frac{1}{6}:\left(\frac{-4}{5}\right)-46\frac{1}{6}:\left(\frac{-4}{5}\right)\)
- Giúp mình nha ^^
so sánh: 2^23+1/2^25+1 và 2^25+1/2^27+1
so sánh:
2^23+1/2^25+2 và 2^25+1/2^27+1
Bài 2 : Tính
a) \(\frac{10}{27}+\frac{7}{23}+0,5-\frac{5}{27}+\frac{16}{23}\)
B) \(\frac{3}{8}.\frac{27}{5}+\frac{51}{5}\frac{3}{8}+19\)
C) \(25.\left(\frac{-1}{5}\right)^3+\frac{1}{5}-2.\left(\frac{1}{2}\right)^2-\frac{1}{2}\)
D) \(\frac{35}{6}:\left(\frac{-4}{5}\right)-\frac{1}{129}:\left(\frac{4}{5}\right)\)
Mọi người giúp mình vs, mình tick cho
