Ta có A - 1 = \(\frac{10^5+4}{10^5-5}-1=\frac{10^5+4-10^5+5}{10^5-5}=\frac{9}{10^5-5}\)
Lại có : B - 1 = \(\frac{10^5+3}{10^5-6}-1=\frac{10^5+3-10^5+6}{10^5-6}=\frac{9}{10^5-6}\)
Vì \(\frac{9}{10^5-5}< \frac{9}{10^5-6}\Rightarrow A-1< B-1\Rightarrow A< B\)
bai 1:tính nhanh : P=\(\frac{\frac{2}{3}-\frac{1}{4}+\frac{5}{11}}{\frac{5}{12}+1-\frac{7}{11}}\)
Bai 2:Thực hiện phép tính: 1-2+3-4+5-6+...+2011-2012
Bai 3:so sánh:A=\(\frac{2011+2012}{2012+2013}\)
B=\(\frac{2011}{2012}+\frac{2012}{2013}\)
bai4:so sánh:A=\(\frac{20^{10}+1}{20^{10}-1}\)
B=\(\frac{20^{10}-1}{20^{10}-3}\)
So sánh hai số A = \(\frac{10^5+4}{10^5-1}\)và B = \(\frac{10^5+3}{10^5-2}\)
So sánh hai số A = \(\frac{10^5+4}{10^5-1}\)và B = \(\frac{10^5+3}{10^5-2}\)
cho A = \(\frac{10^5+4}{10^5-1}\)và B =\(\frac{10^5+3}{10^5-2}\)
so sánh A và B
\(A=\frac{4}{10\cdot2}+\frac{6}{2\cdot20}+\frac{15}{5\cdot20}+\frac{5}{5\cdot40};B=\frac{3}{1\cdot5}+\frac{5}{13\cdot1}+\frac{11}{13\cdot3}+\frac{2}{3\cdot26}\)
So sánh A với B
bài 1 So sánh
a)\(A=\frac{3}{8^3}+\frac{7}{8^4}\) ; \(B=\frac{7}{8^3}+\frac{3}{8^4}\)
b)\(A=\frac{10^{1992}+1}{10^{1991}+1};B=\frac{10^{1993}+1}{10^{1992}+1}\)
c)\(A=\frac{10^7+5}{10^4-8};B=\frac{10^8+6}{10^8-7}\)
d)\(A=\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8};B=\frac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}\)
e)\(A=\frac{2011}{2012}+\frac{2012}{2013};B=\frac{2011+2012}{2012+2013}\)
Cho A\(=\)\(\frac{10^5+4}{10^5-1}\)và B\(=\frac{10^5+3}{10^5-2}\)
Hãy so sánh A và B
Hãy so sánh:
a) A= \(\frac{178}{179}+\frac{179}{180}+\frac{183}{181}\)với 3.
b) A= \(\frac{1+5+5^2+5^3+...+5^{10}+5^{11}}{1+5+5^2+5^3+...+5^9+5^{10}}\)và B=\(\frac{1+7+7^2+7^3+...+7^{10}+7^{11}}{1+7+7^2+7^3+...+7^9+7^{10}}\)
So sánh\(\frac{10^5+4}{10^5-1}\) và \(\frac{10^5+3}{10^5-2}\)
