Ta có:
\(\frac{3}{5.2!}+\frac{3}{5.3!}+\frac{3}{5.4!}+...+\frac{3}{5.100!}\)
\(=\frac{3}{5}.\left(\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}+...+\frac{1}{100!}\right)\)
\(< \frac{3}{5}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\right)\)
\(=\frac{3}{5}.\left(1-\frac{1}{100}\right)\)
\(< \frac{3}{5}.1=\frac{3}{5}=0,6\)
Ta có:
3/5.2!+3/5.3!+.......+3/5.100!
=3/5(1/2!+1/3!+.......+1/100!)
< 3/5(1/1.2+1/2.3+........+1/99.100)
=3/5.(1-1/100)
<3/5=0.6
=> tổng trên<0,6