So sánh
A = \(\dfrac{2022^{2023}+1}{2022^{2024}+1}\) và B = \(\dfrac{2022^{2022}+1}{2022^{2023}+1}\)
\(\dfrac{2022}{2023}.\left(\dfrac{9}{13}-\dfrac{7}{11}\right)+\dfrac{2022}{2023}.\left(\dfrac{17}{13}-\dfrac{4}{17}\right)\)
So sánh: \(\dfrac{2022}{\sqrt{2023}}\) + \(\dfrac{2023}{\sqrt{2022}}\) và \(\sqrt{2022}\) + \(\sqrt{2023}\)
so sánh
\(\dfrac{10^{2023}-3}{10^{2024}-3}\)
và
\(\dfrac{10^{2022}+1}{10^{2023}+1}\)
So sánh:
a) \(\dfrac{-11}{12};\dfrac{17}{-18}\)
b) \(\dfrac{-14}{-21};\dfrac{-60}{-72}\)
c) \(\dfrac{2135}{13790};\dfrac{4}{3}\)
d) \(\dfrac{2022}{2021};\dfrac{10}{9}\)
e) \(\dfrac{35}{36};\dfrac{16}{17}\)
f) -1,3; -1,2
giúp mình với, mình cảm ơn
\(\dfrac{2021}{2021^2+1}và\dfrac{2022}{2022^2+1}\)so sánh
So sánh
a)17/20 và 18/19 b)19/18 và 2023/2022
c)13/17 và 135/175 d)53/63 và 535/636
e)13/15 và 22/25 \(\dfrac{2023}{2023^2+1}và\dfrac{2022}{2022^2+1}\)
mọi người giúp mình với làm ơn
a, N=7-8+9-10+11-12+...+2009-2010
B,P = 1-2-3-4-...2022-2023
a) \(\dfrac{15}{11}\) - (\(\dfrac{5}{7}\) - \(\dfrac{18}{11}\)) + \(\dfrac{27}{7}\)
b) \(\dfrac{39}{5}\)+ (\(\dfrac{9}{4}\) - \(\dfrac{9}{5}\)) - (\(\dfrac{5}{4}\) + 1,2)
c) -1,2 - 0,8 + 0,25 + 5,75 - 2022
d) 0,1 + \(\dfrac{16}{9}\) + 5,1 + \(\dfrac{-20}{9}\)
1. So sánh
a) \(A=\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{2020}}+\dfrac{1}{2^{2021}}\) và B= \(\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{13}{60}\)
b) \(C=\dfrac{2019}{2021}+\dfrac{2021}{2022}\) và \(D=\dfrac{2020+2022}{2019+2021}.\dfrac{3}{2}\)